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What would be the molar ratio in the production of hydrogen iodide gas fromhydrogen and iodide gases, as shown in the following chemical reaction: *H2 (g) + 12 (9)2HI (g)1:1:12:1:21:1:22:1:1

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The chemical reaction of the formation of hydrogen iodide is given:

H2(g) + I2(g) = 2HI (g)

As you can see from the equation, only 1 mole of hydrogen and 1 mole of iodine react to form 2 moles of hydrogen iodide

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