The correct answer is 3.6×10⁷ (1/Ωm)
Given,
The length of the aluminum wire, l=5.5 m
The resistance of the wire, R=0.40 Ω
The resistivity of the wire, ρ=2.82×10⁻⁸ Ωm
The resistivity is given by the inverse of the conductivity of a material.
Thus the conductivity of the given wire is,
![c=(1)/(\rho)](https://img.qammunity.org/2023/formulas/physics/college/jqoxe4f55509b4h3p0m4twbu4w68yjhdle.png)
On substituting the known values,
![\begin{gathered} c=(1)/(2.82*10^(-8)) \\ =3.6*10^7\text{ (1/}\Omega\text{m)} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/jwuu29zm92zdmumywnk6a7dysfrjvcwvpx.png)
Therefore the conductivity of the given aluminum wire is (1/Ωm)