it is given that,
the distance cover by may is 6 3/4 miles = 27/4 miles,
and fot noah , 4 1/2 miles = 9/2 miles,
so, the relation between the both rides is,
take ratio
![\frac{\text{may}}{\text{noah}}=((27)/(4))/((9)/(2))](https://img.qammunity.org/2023/formulas/mathematics/high-school/l2flq96s32yzqzjs320n3ufitgi99wbkmj.png)
![(may)/(noah)=(27)/(18)=(3)/(2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/aowv8uji1a60x90gnhnba7kmonfaydqclc.png)
![\begin{gathered} \text{noah = }(2)/(3)\text{may} \\ \text{mays ride = }(3)/(2)\text{noah' ride} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/vi0ofjc63tst5smy0mnbctr1wmvkotrayy.png)
thus, Noah's bike ride was2/3 times of Mays bike ride
and
thus, the answer is Mays bike ride was 3/2 times of noah's bike ride.