Question

How do you turn 5x-25y=3 into slope intercept form?

Answer 1

Writing the given equation in slope-intercept form we have;

`\begin{gathered} y=(x)/(5)-(3)/(25) \\ or \\ y=(1)/(5)x-(3)/(25) \end{gathered}`

Step-by-step explanation:

Given the linear equation;

`5x-25y=3`

We want to turn the given linear equation to slope-intercept form.

`\begin{gathered} y=mx+b \\ m=\text{slope} \\ b=y-\text{intercept} \end{gathered}`

To do that, let us make y the subject of formula;

subtract 5x from both sides;

`\begin{gathered} 5x-5x-25y=-5x+3 \\ -25y=-5x+3 \end{gathered}`

divide both sides by -25 (the coefficient of y);

`\begin{gathered} (-25y)/(-25)=(-5x)/(-25)+(3)/(-25) \\ y=(x)/(5)-(3)/(25) \end{gathered}`

Therefore, writing the given equation in slope-intercept form we have;

`y=(x)/(5)-(3)/(25)`