Question

Which of these is a pair of coordination isomers (aka ionization isomers)?

a. Na2[NiBr2Cl2] and K2[NiBr2Cl2]
b. [Ni(NH3)3Br]Cl and [Ni(NH3)3Cl]Br
c. [Ni(NH3)3(H2O)]SO4 and [Ni(NH3)2(H2O)2]SO4

Which of these pairs are linkage isomers??

a. [Pt(Cl)2(SCN)4]^4- and [Pt(Cl)2(NCS)4]^4-
b. [Pt(Cl)2(SCN)4]^4- and [Pt(Cl)4(SCN)2]^4-
c. K4[Pt(Cl)2(SCN)4] and Na4[Pt(Cl)2(SCN)4]

Answer 1

Answer:
`[Ni(NH_3)_3Br]Cl` and
`[Ni(NH_3)_3Cl]Br` are ionization isomers.

`[Pt(Cl)_2(SCN)_4]^(4-)` and
`[Pt(Cl)_2(NCS)_4]^(4-)` are linkage isomers.

Step-by-step explanation:

Ionization isomerism occur when a ligand that is bound to the metal center exchanges places with an anion or neutral molecule that was originally outside the coordination complex

Thus
`[Ni(NH_3)_3Br]Cl` and
`[Ni(NH_3)_3Cl]Br` are ionization isomers.

Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand.

Thus
`[Pt(Cl)_2(SCN)_4]^(4-)` and
`[Pt(Cl)_2(NCS)_4]^(4-)` are linkage isomers.