We have a function f(x)=3x-2, that is a line, but is only defined for a domain D = {-3,1,5}
Then, we will have only 3 points for this function: the points (x,f(x)) that relate the x of the domain D to their corresponding image.
We can calculate f(x) for each value of the domain:
![x=-3\longrightarrow f(-3)=3(-3)-2=-9-2=-11](https://img.qammunity.org/2023/formulas/mathematics/college/gkhjni0r2tcl883tsz8fu2j8nkktujesx4.png)
![x=1\longrightarrow f(1)=3(1)-2=3-2=1](https://img.qammunity.org/2023/formulas/mathematics/college/crmixe07m6b3tgz7pj0dleqfiybzwcj5fr.png)
![x=5\longrightarrow f(5)=3(5)-2=15-2=13](https://img.qammunity.org/2023/formulas/mathematics/college/2jqoui7nj8bteycg7ouzwesi8n61cbzh6u.png)
Then, we have the three points: (-3,-11), (1,1) and (5,13).
Then, we cn graph this points in a graph where y=f(x):