Question

An Aluminium stick of length 1.5 m is cooled from 200 C to -1800 C. Find the final length if its coefficient of linear expansion is 23×10-6/K?

Answer 1

1.454 m

Step-by-step explanation:

From the question,

L₂ = L₁+α(T₂-T₁).................. Equation 1

Where L₂ = Final Length, L₁ = Initial Length, α = Coefficient of Linear expansion, T₁ = Initial Temperature, T₂ = final Temperature.

Given: L₁ = 1.5 m, α = 23×10⁻⁶ K⁻¹, T₁ = 200 °C, T₂ = -1800 °C

Substitute these values into equation 1

L₂ = 1.5+[23×10⁻⁶ ×( -1800-200)

L₂ = 1.5+(23×10⁻⁶×2000)

L₂ = 1.5+(-0.046)

L₂ = 1.5-0.046

L₂= 1.454 m.