in parallelogram ABCD, AC= 3x-17 and AO= 5 Find x.
we know that
In a parallelogram opposite sides are congruent and the diagonals bisect each other
In this problem
I will assume that AC is a diagonal of the parallelogram and O is the intersection both diagonals
that means
AO=AC/2
substitute the given values
5=(3x-17)/2
solve for x
10=3x-17
3x=10+17
3x=27
x=9