To solve the question, first, we have to standardize the data, meaning, we will compute the z-scores that correspond to 43, 38, 37, and 42.
Z-scores:
![\begin{gathered} Z_(43)=(43-41.2)/(6.1)\approx0.29508, \\ Z_(38)\approx-0.52459, \\ Z_(37)\approx=-0.68852, \\ Z_(42)\approx0.13115. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5dshvodnd4zl7k9i93qv4o0g2az98x8psu.png)
Now, using tables, we get the area under the normal curve that corresponds to each z-score to get the percentages for questions a, and b:
a) x<43 corresponds to 0.61603, therefore, 61.60% is below 43 inches.
b) x>38 corresponds to 0.70007, therefore, 70.01% is above 38 inches.
Now, using tables, we get that:
x<37 corresponds to 0.24556, and x<42 corresponds to 0.55217, therefore
![0.55217-0.24556](https://img.qammunity.org/2023/formulas/mathematics/college/746uhi8lu9x2ptv1f1ge3as1pnolh87vga.png)
corresponds to the interval between 37 and 42 inches.
Answer:
a) 61.60%,
b) 70.01%,
c) 30.67%.