Question

A light beam is shone into a mystery material . the light beam has an incident angle of 48 degree and a refracted angle of 27 degrees. If n1 = 1.00, what is n2? A) 1.78B) 0.56C) 1.64D) 0.61

Answer 1

Given:

The incident angle is,

`i=48\degree`

The refracted angle is

`r=27\degree`

The refractive index of the first medium is,

`n_1=1.00`

To find:

The refractive index of the second medium

`n_2`

Step-by-step explanation:

According to Snell's law,

`\begin{gathered} n_1sini=n_2sinr \\ n_2=(n_1sini)/(sinr) \end{gathered}`

Substituting the values we get,

`\begin{gathered} n_2=(1.00* sin48\degree)/(sin27\degree) \\ =1.64 \end{gathered}`

Hence, the refractive index of the second medium is 1.64.