Question

7. The graph of a quadratic equation has x - intercepts at (-5,0) and (1,0). Which of the following could represent the equation described? y = (x + 5)(x-1) O y=x2-5 y = (x - 5)(x + 1) y = 5x2-1

Answer 1

a) (-5, 0) (1, 0)

y = (x + 5)(x - 1) This equation is the solution to your question.

Point 1

0 = (-5 + 5)(-5 - 1) 0 = (1 + 5)(1 - 1)

0 = (0)(-6) 0 = (6)(0)

0 = 0 0 = 0

Both points are solutions for this equation so this is the solution to these points.