Question

What is an equation of the line that passes through the point (-8, 0) and is parallel

to the line x + 2y = 14?

Answer 1

Equation of line is given as y = mx + c, where m is the gradient/slope and c is the y-intercept.

First rearrange x + 2y = 14 into y = mx + c form.

x + 2y = 14

2y = -x + 14

y = -1/2x + 7

Parallel lines have the same gradient so equation of line is y = -1/2x + c.

Substitute (-8,0) into the equation to find c.

0 = -1/2(-8) + c

c = -4

Hence, equation of line is y = -1/2x - 4.