Question

What is the x and the y and the z

Answer 1

Given:

`\begin{gathered} x-2y+z=-3\ldots\ldots\ldots(1) \\ y+2z=2\ldots\ldots\ldots(2) \\ x+y+3z=3\ldots\ldots\ldots(3) \end{gathered}`

To find the value of x,y, and z:

Subtract (3) from (1) we get,

`-3y-2z=-6\ldots\ldots\ldots(4)`

Adding (2) and (4) we get,

`\begin{gathered} -2y=-4 \\ y=2 \end{gathered}`

substitute y=2 in the equation (2) we get,

`\begin{gathered} 2+2z=2 \\ 2z=0 \\ z=0 \end{gathered}`

Substitute y=2 and z=0 in equation (1) we get,

`\begin{gathered} x-2(2)+0=-3 \\ x-4=-3 \\ x=1 \end{gathered}`

Hence, the answer is, x=1, y=2, and z=0