a)
We would simplify by applying the following laws of exponents
a^b * a^c = a^(b + c)
(a^b)^c = a^(bc)
BY applying these laws, we have
(5^6b^-12)(3^-2b^-10)
Recall,
a^-1 = 1/a
a^-2 = 1/a^2
Thus, we have
(15625b^-12)(1/3^2b^-10)
= 15625/9 * b^(- 12 - 10)
= 15625/9(b^-22)