We must find the value k such that Q(x) = (x+2) is a factor of the cubic polynomial:
![P(x)=x^3-6x^2-11x+k](https://img.qammunity.org/2023/formulas/mathematics/college/4sxlcjt3ayn0cel0mzwjxrco5hxdqnci3i.png)
Now, if (x+2) is a factor of the polynomial P(x), then the rest R of the following division must be zero,
![(P(x))/(Q(x))](https://img.qammunity.org/2023/formulas/mathematics/college/6kql4nuqg48cf3uwj37t1vgq8kf0rh325f.png)
So we must compute the division between the polynomials and check the condition to have R = 0. We compute the quotient by applying the method of synthetic division. Doing that we have:
From the division we see that the rest is:
![R=k-10](https://img.qammunity.org/2023/formulas/mathematics/college/zted691kegyof2ld63io5j1q02q18qszry.png)
The condition is that the rest R must be equal to zero, so:
![R=k-10=0\Rightarrow k=10](https://img.qammunity.org/2023/formulas/mathematics/college/vuq2apctcl8hz22fts7z2c22zemxi3blsd.png)
Answer: k = 10