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Youfu · Answer 1 · 2023-12-13T06:36:46+0000

Given the length of the radius EG = 15 feet

$Using\text{ the formula of length of an arc is }(\theta)/(360)\text{ }*\text{ 2}\pi\text{r}$

The angle at the centre is twice the angle at the circumference

$\begin{gathered} [tex]\begin{gathered} \theta\text{ = 2 }*52^0 \\ \theta=104^0 \\ \text{Therefore }(104)/(360)\text{ }*\text{ 2 }*\text{ }\frac{22}{7\text{ }}\text{ }*\text{ 15} \\ =\text{ 27.23 f}eet \end{gathered}$

Hence the approximate length of EG = 27 feet

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