Question

Write the equation of the line that goes through the origin and the point (-5, -3).

Answer 1

The equation of the line in the slope-intercept form is given by:

`\begin{gathered} y=mx+b \\ where \\ m=slope \\ b=y-intercept_{}_{} \\ \end{gathered}`

Since the line goes through the origin:

`b=0`

We can find the slope using the following formula:

`\begin{gathered} m=(y2-y1)/(x2-x1) \\ where \\ (x1,y1)=(-5,-3) \\ (x2,y2)=(0,0) \\ so\colon \\ m=(0-(-3))/(0-(-5))=(3)/(5)=0.6 \end{gathered}`

Therefore, the equation of the line is:

`\begin{gathered} y=(3)/(5)x \\ or \\ y=0.6x \end{gathered}`