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In 4-6, solve each system using substitution

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\begin{gathered} 3.25x-1.5y=1.25\ldots eqn(i)\text{ } \\ 13x-6y=10\ldots.eqn(ii) \\ \mu\text{ltiplying eqn(1) by 4, we have,} \\ 13x-6y=5\ldots eqn(iii) \\ \text{substituting / putting eqn(}iii)\text{ into eqn(i}i)\text{ we have} \\ \text{The system will colapse, so it follow that the question is trivial.} \end{gathered}

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