We have the series: 3, 4.5, 6, 7.5, 9, ...
First, we have to find the relation between the terms.
We see that, if we substract from one term, the previous term, we get a constant:
![a_n-a_(n-1)=1.5](https://img.qammunity.org/2023/formulas/mathematics/college/uprtibz70xn7y4u15d7a1qmbumuabglsxi.png)
This is the common difference, so we can write:
![a_n=a_(n-1)+1.5](https://img.qammunity.org/2023/formulas/mathematics/college/1h9hcecztd899pg8jts9pibpdcgk06xngb.png)
This is the recursive formula.
We have to find the explicit formula, that only depends on n.
To do so, we start by writing:
![\begin{gathered} a_1=3 \\ a_2=4.5=3+1.5_{} \\ a_3=6=4.5+1.5=3+1.5+1.5=3+2\cdot1.5 \\ a_4=3+3\cdot1.5 \\ a_n=3+(n-1)\cdot1.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5sm39u1a2g7l8h8gcepi76w5u6nqnh57hd.png)
Then, the explicit formula for the nth term is:
![a_n=3+(n-1)\cdot1.5=1.5+1.5n=1.5(1+n)](https://img.qammunity.org/2023/formulas/mathematics/college/cbckbq0iu6lplsmbx1xrlvxkgg86aweq1z.png)
Any of this expression is valid.