![g(x)=5x^4+7x^3+4x^2-3x-4](https://img.qammunity.org/2023/formulas/mathematics/high-school/q26rtaecvef9cwq28677k26uzr4xnm32pi.png)
Since the polynomial g(x) is a polynomial with integer coefficients and if p/q is a zero of:
![\begin{gathered} G(x)(G((p)/(q))=0),\text{ then p is a factor of the constant term of }G(x)\text{ and q} \\ is\text{ a factor of the leading coefficient} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/y43wokjfgy7r7f98da4v1drzijddh1bv06.png)
So, we have to find all integer factor of the constant term, in this case: -4 and the leading coefficien, in this case: 5, and find all possible quotients p/q where p is a factor of the constant and q is the factor of the leading coefficient:
![\begin{gathered} \text{Integers factor of -4: }\pm1,\text{ }\pm2,\text{ }\pm4 \\ \text{Integers factor of 5: }\pm1,\text{ }\pm5 \\ \text{Then, the possible rational roots are:} \\ \pm1,\pm2,\pm4,\pm5,\pm(4)/(5),\text{ }\pm(1)/(5),\text{ }\pm(2)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/3s2z40ccmcxsf1m0tgnlng25spsnf5g6iv.png)
To find which of these are roots, simply substituing on the original equation:
By substitung all the values of possible roots, we can state that this polynomial doesnt' have rational zeros.