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Given n(A) = 288, n(B) = 183, and n(AU B) = 434, find n(A∩ B).a) 37b) None of thesec) 539d) 329

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We have to find n(A∩B), which is the number of elements that belong both to A and B.

We can use the following relation:


n(A\cup B)=n(A)+n(B)-n(A\cap B)

We can then calculate n(A∩B) as:


\begin{gathered} n(A\cup B)=n(A)+n(B)-n(A\cap B) \\ n(A\cap B)=n(A)+n(B)-n(A\cup B) \\ n(A\cap B)=288+183-434 \\ n(A\cap B)=37 \end{gathered}

Answer: 37 [Option a]

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