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A serving of banana contains 0.7 grams of protein, 0.2 grams of fat, and 13.5 grams ofcarbohydrates. A serving of mandarin oranges contains 0.5 grams of protein, 0.3 grams of fat,and 8.5 grams of carbohydrates. A serving of grapes contains 0.3 grams of protein, 0.2 grams offat, and 8 grams of carbohydrates. How many servings of each are needed to supply exactly 3.2grams of protein, 1.5 grams of fat, and 60.5 grams of carbohydrates?

User Degratnik
by
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1 Answer

3 votes

EXPLANATION

Let's see the facts:

Banana Composition:

0.7 grams of protein

0.2 grams of fat

13.5 gram of carbohydrates

Mandarin composition:

0.5 gram of protein

0.3 grams of fat

8.5 grams of carbohydrates

Grapes composition:

0.3 grams of protein

0.2 grams of fat

8 grams of carbohydrates

Needed---->

3.2 grams of protein

1.5 grams of fat

60.5 gram of cabohydrates

Let x be the servings of bananas, y the servings of mandarin and z the serving of grapes, we will have a system of equation with the following form:

(1) 0.7x + 0.5y + 0.3z = 3.2

(2) 0.2x + 0.3y + 0.2z = 1.5

(3) 13.5x + 8.5y + 8z = 60.5

Now, we must solve for x,y and z;

Isolate x for 0.7x + 0.5y + 0.3z = 3.2:

Multiply both sides by 10:

0.7x*10+0.5y*10+0.3z*10=3.2*10

Refine:

7x + 5y + 3z = 32

Subtract 5y + 3z from both sides:

7x + 5y + 3z - (5y + 3z) = 32 - (5y+3z)

Simplify:

7x = 32 - 5y -3z

Divide both sides by 7:

7x/7 = 32/7 - 5y/7 -3z/7

Simplify:

x= (32-5y-3z)/7

Substitute x= (32-5y-3z)/7

0.2[(32-5y-3z)/7] + 0.3y + 0.2z = 1.5

13.5[(32-5y-3z)/7] + 8.5y + 8z = 60.5

Simplify 0.2[(32-5y-3z)/7] + 0.3y + 0.2z = 1.5:

Multiply the fractions: a*b/c = (a*b)/c

0.2[(32-5y-3z)/7] = 0.02857* (32-5y-3z)

Expand 0.02857* (32-5y-3z):

Distribute parentheses:

=0.02857*32 -0.02857*5y -0.02857*3z

Multiply the numbers:

=0.91428 - 0.14285y - 0.08571z + 0.3y + 0.2z = 1.5

Add terms and simplify:

0.15714y + 0.11428z + 0.91428 = 1.5

Let's continue with the third equation:

13.5[(32-5y-3z)/7] + 8.5y + 8z = 60.5

Distribute terms:

1.92857*(32-5y-3z) + 8.5y + 8z = 60.5

Distribute parentheses:

1.92857*32 -5*1.92857y -1.92857*3z + 8.5y + 8z = 60.5

Simplify:

61.71428 -9.64285y -5.78571z + 8.5y + 8z = 60.5

Adding similar terms:

-1.14285y +2.21428z +61.71428 = 60.5

Our system of equations is now:

0.15714y+0.11428z+0.91428s =1.5

-1.14285y+2.21428z+61.71428 =60.5

Isolate y for 0.15714y+0.11428z+0.91428s =1.5:

Subtract 0.11428 from both sides:

0.15714y+0.11428z+0.91428 -0.11428z=1.5-0.11428z

Simplify:

0.15714y+0.91428=1.5-0.11428z

Subtract 0.91428 from both sides:

0.15714y+0.91428-0.91428 =1.5-0.11428z-0.91428

Simplify:

0.15714y=-0.11428z+0.58571

Divide both sides by 0.15714:

0.15714/0.15714y=-0.11428/0.15714z+0.58571/0.15714

Simplify:

y=(-0.11428z+0.58571)/0.15714

Substitute y=(-0.11428z+0.58571)/0.15714:

-1.14285*[(-0.11428z+0.58571)/0.15714]+2.21428z+61.71428=60.5

Simplify:

3.04545z+57.45454=60.5

Isolate z for 3.04545z+57.45454=60.5:

Subtract 57.45454 from both sides

3.04545z+57.45454-57.45454 =60.5-57.45454

Simplify:

3.04545z=3.04545

Divide both sides by 3.04545:

Simplify:

z=1

For y=(-0.11428z+0.58571)/0.15714

Substitute z=1

y=(-0.11428*1+0.58571)/0.15714

Simplifying:

y=3

For x= (32-5y-3z)/7 substitute y=3 and z=1

x= (32-5*3-3*1)/7

Simplifying:

x=2

The solutions to the systems of equations are:

x=2, y=3 and z=1

So, in order to supply exactly 3.2 grams of protein, 1.5 grams of fat and 60.5 grams of carbohydrates, we need 2 servings of banana, 3 servings of mandarin and 1 serving of grapes.

User Hmmm
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