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35 votes
If ab = 9 and a² + b² = 81, then (a+b)² = ?​

User Ilyas Patanam
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1 Answer

20 votes
20 votes

Answer:

99

Explanation:

Through some clever algebra, we can combine our first two equations using the fact that


(a+b)^2=a^2+2ab+b^2

We have the a² and the b² in the equation
a^2+b^2=81, and we almost have a 2ab in the equation
ab=9. To get that 2ab, we can simply double both sides of the first equation to get
2ab=18. From there, we'll add the first two equations together, giving us the summed equation


a^2+b^2+2ab=81+18\\a^2+2ab+b^2=99

And since
(a+b)^2=a^2+2ab+b^2, we can equivalently say that


(a+b)^2=99

User QWERTYL
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