Okey, here is a list of all the posible combinations when you throw the die two times. Then I makde the sum for T and I put the probablitity of each result
Is only missing to add the probablitity for each value of T
So in most of the cases is 0.04 because:
![0,04=(1)/(5)\cdot(1)/(5)](https://img.qammunity.org/2023/formulas/mathematics/college/mbui5hkj1of0xiau5dbmbngolrnhux0h5i.png)
The probability of geting any number is 1/5, then to get an exact combination you have to multiply both cases.
For 4, as there where two 4 you multiply the probability times 2, 2/5