Question

10 gram sample of methane (CH 4 ) has the same number of molecules as 10 gram sample of O 2

Answer 1

The given question is incomplete. The complete question is:

10 gram sample of methane
`(CH_4)` has the same number of molecules as 10 gram sample of
`O_2`. True or False

Answer: Thus the statement is False.

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}`

1.
`\text{Number of moles for methane}=(10g)/(16g/mol)=0.625moles`

Now 1 mole of
`CH_4` molecule contains =
`6.023* 10^(23)` of molecules

0.625 mole of
`CH_4` molecule contains =
`(6.023* 10^(23))/(1)* 0.625=3.76* 10^(23)` molecules

2.
`\text{Number of moles for oxygen}=(10g)/(32g/mol)=0.3125moles`

Now 1 mole of
`O_2` molecule contains =
`6.023* 10^(23)` of molecules

0.3125 mole of
`O_2` molecule contains =
`(6.023* 10^(23))/(1)* 0.3125=1.88* 10^(23)` molecules

The number of molecules are different.