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How many distinct rearrangements of the letters in happiness are there? Give your answer as an integer.

User Binoj T E
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1 Answer

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Given the word "HAPPINESS";

There are nine letters in HAPPINESS but with two letters reocurrring more than once.

The number of distinct rearrangement of the letters is;


(9!)/(2!2!)

Thus, we simplify further. We have;


\begin{gathered} (9!)/(2!2!)=(9*8*7*6*5*4*3*2!)/(2*1*2!) \\ (9!)/(2!2!)=90,720 \\ \end{gathered}

FINAL ANSWER: 90,720

User Alexkaessner
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