Question

The weak ionization constant (Ka)for HCO3 is equal to:AB[H3O+][CO32- ](HCO3-)[HCO3 -[H3O+][CO32-]

Answer 1

A

`(\lbrack H_3O^+\rbrack)(\lbrack C(O_3)^2\rbrack)/(\lbrack HCO_3^-\rbrack)`

Step-by-step explanation

The ionization of HCO₃⁻ in H₂O is:

`HCO₃⁻+H₂O\rightleftarrows H_3O^++CO₃^(2-)`

The general ionization constant, Ka is given as:

`Ka=(\lbrack Products\rbrack)/(\lbrack Reactants\rbrack)`

Hence, the ionization (Ka) of HCO₃⁻ is equal to:

`(\lbrack H_3O^+\rbrack\lbrack CO_3^(2-)\rbrack)/(\lbrack HCO_3^-\rbrack)`

Option A is the correct answer.