Question

Randall wants to mix 54 Ib of nuts worth $1 per lb with some nuts worth $5 per Ib to make a mixture worth $4 per lb. How many pounds of $5 nuts must he use?

Answer 1

Let:

x = no. of lb of $5 nuts required.

resulting mixture = x + 54

Hence:

`54*\text{\$1}+\text{ \$5x}=(x+54)*\text{\$4}`

Solving for x:

`\begin{gathered} 54+5x=4x+216 \\ 5x-4x=216-54 \\ x=162 \end{gathered}`

ANSWER

Randall must use 162 lb of $5 nuts