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3a - √(a² + b²)When a = -6 and b = 8Evaluate the expression

User Rob J
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1 Answer

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We have to evaluate the expression:


3a-√(a^2+b^2)

where a = -6 and b = 8.

To do that we replace a and b with the corresponding values and then calculate the expression:


\begin{gathered} 3(-6)-√((-6)^2+8^2) \\ -18-√(36+64) \\ -18-√(100) \\ -18-10 \\ -28 \end{gathered}

Answer: -28

User Syone
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