Given:
The points are,

The polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the centre of dilation, resulting in the image MNOPQ.
To find:
The slope of M'N'.
Step-by-step explanation:
After the dilation by a scale factor of 0.8 with the origin,
The points become,

Using the slope formula,

Therefore, the slope of M'N' is 1.
Final answer:
The slope of M'N' is 1.