Question

If t=5pi/3, find the terminal point P(x,y) on the unit circle.

Answer 1

`((1)/(2),-\frac{\sqrt[]{3}}{2})`

Step-by-step explanation:

The given angle:

`(5\pi)/(3)=(5*180)/(3)=300^0`

For an angle in standard position on the unit circle, the location of the terminal point will be:

`\begin{gathered} (x,y)=(\cos 300^0,\sin 300^0) \\ =((1)/(2),-\frac{\sqrt[]{3}}{2}) \end{gathered}`