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A compound is 48.6 % C, 8.2 % H, and 43.2 % O by mass. Calculate the empirical formula of this compound.

User Mash
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1 Answer

8 votes
Answer:
C2H3O
Step-by-step explanation
:
C. H. O
48.6. 8.2. 43.2
r.a.m 12. 1. 16
no.of 48.4÷12. 8.2÷1. 43.2÷16
moles
4.05÷2.7. 8.2÷2.7. 2.7÷2.7
2. 3. 1
Therefore C2H3O
User Chirantan
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