Answer:
The cost of one ft² of grass sod is $12 and the cost of one pot of ivy is $4.
Step-by-step explanation:
Step 1: Define your variables:
• Let the cost of one ft² of grass sod = g
,
• Let the cost of one pot of ivy = p
Step 2: Derive the equations
Pranav spent $196 on 12 ft² of grass sod and 13 pots of ivy.
![12g+13p=196\cdots(1)](https://img.qammunity.org/2023/formulas/mathematics/college/l9a6l9fykiycy9po70evumdxdppel7jdp6.png)
Juli spent $76 on 4 ft² of grass sod and 7 pots of ivy.
![4g+7p=76\cdots(2)](https://img.qammunity.org/2023/formulas/mathematics/college/8ghs9tvu1idyrbsmsw6kua1fdje35e5e3d.png)
Step 3: Solve the system of equations
![\begin{gathered} 12g+13p=196 \\ 4g+7p=76 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3uc96ayxazyu9wib20j23a577nfimwjnbv.png)
Multiply the first equation by 1 and the second equation by 3:
![\begin{gathered} 12g+13p=196 \\ 12g+21p=228 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/csv4urpe41j9uzjtbfzp7gvfbu2jvwt4xu.png)
Subtract:
![\begin{gathered} 21p-13p=228-196 \\ 8p=32 \\ p=(32)/(8) \\ p=\$4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/19ljymlqsvcvh67bslmxm79o7ekq4mxf66.png)
Next, substitute p=4 to solve for g:
![\begin{gathered} 12g+13p=196 \\ 12g=196-13p \\ 12g=196-13(4) \\ 12g=144 \\ g=(144)/(12) \\ g=\$12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3cmci745zre1be2hklw4bgykkrbda0ayzo.png)
The cost of one ft² of grass sod is $12 and the cost of one pot of ivy is $4.