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The lengths of each side of rectangle T are 4 times the lengths of each side of rectangle R. How many times larger is the area of rectangle T compared to the area of rectangle R?

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Given information:

Two rectangles: Rectangle T and R

Since it is said on the question that the lengths of each side of Rectangle T are 4 times the length of each side of Rectangle R, we can say that Rectangle T is bigger/larger than Rectangle R.

To get the area of a rectangle, we have the following formula to use:


A=length* width

The area of Rectangle T is:


\begin{gathered} A=length* width \\ A=4x*4y \\ A=16xy \end{gathered}

The area of Rectangle R is:


\begin{gathered} A=length* width \\ A=x* y \\ A=xy \end{gathered}

Therefore, the area of Rectangle T is 16 times larger than the area of Rectangle R.

The lengths of each side of rectangle T are 4 times the lengths of each side of rectangle-example-1
User Louay Sleman
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