Question

A set of data items is normally distributed with a mean of 80 and a standard deviation of 7 Convert 80 to a z-score.

Answer 1

Step-by-step explanation:

We are to convert the given data to a z-score

To do so, we will use the formula:

`\begin{gathered} z=(x-\mu)/(\sigma) \\ \end{gathered}`

Where

`\begin{gathered} x=observed\text{ value=80} \\ \mu=mean\text{ score=80} \\ \sigma=standard\text{ deviation=7} \end{gathered}`

Thus

`\begin{gathered} z_(80)=(80-80)/(7)=(0)/(7)=0 \\ z_(80)=0 \end{gathered}`

The z-score is 0