Question

SiO2(s) + 3C(s) —-> SiC(s) + 2CO(g) Determine the limiting reagent when 60.0 grams of SiO2 reacts with 60.0 grams of carbon. A) There is no limiting reagent. B) CC) SiCD) SiO2

Answer 1

Step-by-step explanation:

First, we need to transform 60g of SiO2 and 60 g of C into moles.

For this, we will use the following fomula: n=m/MM

MM of SiO2 = 60 g/mol

MM of C = 12 g/mol

SiO2 :

n = 60/60 = 1 mol

C:

n = 60/12 = 5 mol

The equation tells us that:

SiO2(s) + 3C(s) —-> SiC(s) + 2CO(g)

1 mole of SiO2 reacts with 3 moles of C. It means that the limiting reactant in this case is SiO2, because we have excess of C (we have 2 moles more).

Answer: D) SiO2.