Question

For the triangle below, if side AB = 16x - 7 and side AC = 12x + 1, then x = _____.

Answer 1

`x=2`

Step-by-step explanation

From the given triangle;

Side AC and side AC are equal;

`\angle ABC=\angle ACB`

Hence;

`\begin{gathered} AC=AB \\ AB=16x-7 \\ AC=12x+1 \\ 16x-7=12x+1 \end{gathered}`

Add 7 to both sides;

`\begin{gathered} 16x-7=12x+1 \\ 16x-7+7=12x+1+7 \\ 16x=12x+8 \end{gathered}`

Subtract 12x from both sides;

`\begin{gathered} 16x=12x+8 \\ 16x-12x=12x+8-12x \\ 4x=8 \end{gathered}`

Divide both sides by 4;

`\begin{gathered} (4x)/(4)=(8)/(4) \\ x=2 \end{gathered}`

Therefore, x is 2