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If the length of a rectangle is seven feet less than the width and the perimeter is 78feet, find the width of the rectangle.

User WebXL
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1 Answer

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For this problem we know that the lenght of a rectangle is 7 ft less than the width who represent this equation:


L=w-7

With L the lenght and w the width. We also know that the perimeter of the rectangle is given by 78 ft and we need to find the width. The perimeter is defined as:


P=2L+2w

If we replace the condition of L=w-7 we got:


P=2(w-7)+2w=2w-14+2w=4w-14

Since we know the value of the perimeter we have:


78=4w-14

And we can solve for w and we got:


w=(78+14)/(4)=23ft

And the final answer for this case would be width =23ft

User Adwiv
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