Let the numbers are x and y
The product of the numbers = 294
So,

The quotient of the numbers = 6
So,

Substitute with x = 6y into the first equation:
So,

Solve for y:
![\begin{gathered} 6y^2=294 \\ y^2=(294)/(6)=49 \\ \\ y=\sqrt[]{49}=\pm7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3dx8r6slqa1o21334gyfokdgurm9vpfipb.png)
Now, substitute with y to find x

So, the answer will be:
The numbers are { 42 and 7 } or { -42, -7 }