Question

If I contain 3 moles of gas in a container with a volume of 150,2 liters and at a temperature of318 K, what is the pressure inside the container in mmHg?

Answer 1

In this question we can use the ideal gas law equation, which is:

PV = nRT

Where:

P = pressure

V = volume in Liters, 150.2 L

n = number of moles, 3 moles

R = the constant for gases, 0.082 L atm/mol K

T = temperature in kelvin, 318 K

Now we only need to use these values in the equation

P * 150.2 = 3 * 0.082 * 318

150.2P = 78.23

P = 0.52, but this answer is in atm, so 0.52 atm

Now we need to transform atm to mmHg, which is 1 atm = 760 mmHg

1 = 760

0.52 = x mmHg

x = 395.2 mmHg of pressure