Question

If the gas and piston above has volume of 20.0L at a temperature of 25c what is the volume of that gas when it os heated to 100C if the pressure remain constant?

Answer 1

Given that;

If the gas and piston has volume of 20.0L at a temperature of 25°C

To find the volume of the gas when heated tom 100°C, we will apply Charles law formula, which is

`\begin{gathered} (V_1)/(T_1)=(V_2)/(T_2) \\ V_1\text{ is the first volume} \\ T_1\text{ is the first temperature} \\ V_2\text{ is the second volume} \\ T_2\text{ is the second temperature} \end{gathered}`

Where

`\begin{gathered} V_1=20.0\text{ L} \\ T_1=25\degree C \\ T_2=100\degree C \end{gathered}`

Substitute the values of the variables into the Charles law formula

`\begin{gathered} (V_(1))/(T_(1))=(V_(2))/(T_(2)) \\ (20.0)/(25)=(V_2)/(100) \\ Crossmultiply\text{ } \\ V_2=(100*20.0)/(25)=80.0\text{ L} \\ V_2=80.0\text{ L} \end{gathered}`

Hence, the answer is 80.0 L