Question

What is the axis of symmetry and vortex of the problem below

Answer 1

The axis of symmetry is x = -2

The vertex is (-2, 5)

Step-by-step explanation:

For a quadratic equation of the form:

`y=ax^2+bx+c`

The formula for the axis of symmetry is:

`A_(symmetry)=-(b)/(2a)`

In this case, a = -1 and b = -4

Thus:

`A_(symmetry)=-(-4)/(2(-1))=-(4)/(2)=-2`

Thus, the axis of symmetry is x = -2

To find the vertex, we need to find the value of y in the axis of symmetry. Then, we need to evaluate the equation for x = -2:

`y=-(-2)^2-4(-2)+1=-4+8+1=5`

The vertex is (-2, 5)