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What is the pH of a 0.0075 molar solution of ammonia (NH3)? given:publish =4.75. ​

User Jason Higgins
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1 Answer

21 votes
21 votes

Answer:

10.57

Step-by-step explanation:

Step 1: Given and required data

  • Concentration of NH₃ (Cb): 0.0075 M
  • Basic dissociation constant for NH₃ (Kb): 1.8 × 10⁻⁵

Step 2: Write the basic dissociation reaction for NH₃

NH₃(aq) + H₂O(aq) ⇄ NH₄⁺(aq) + OH⁻(aq)

Step 3: Calculate the concentration of OH⁻

We will use the following expression.

[OH⁻] = √(Kb × Cb)

[OH⁻] = √(1.8 × 10⁻⁵ × 0.0075 M) = 3.7 × 10⁻⁴ M

Step 4: Calculate the concentration of H⁺

We will use the water ion product.

Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴/3.7 × 10⁻⁴ = 2.7 × 10⁻¹¹ M

Step 5: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺] = -log 2.7 × 10⁻¹¹ = 10.57

User Matt Davison
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