Question

In a experiment of 2.35 g of NH3 are allowed to react with 9.89 g of O2. Write the formula of the limiting reagent and find the number of grams of NO formed

Answer 1

The associated equation for the reaction is:

Convert all amounts in grams to moles:

Now, divide each amount in moles by the coefficient of each compound. The smaller result will be the limiting reagent:

The formula of the limiting reagent is NH3.

The number of grams of NO formed can be found from 2.35g of NH3, which is the limiting reagent:

There are 0.41 grams of NO formed.