Question

If the ball lands at the same level from which he was kicked what amount of time was it in the air

Answer 1

Given that the speed of the ball is v = 15.6 m/s

The angle is between the ground and the ball is 60 degrees.

The acceleration due to gravity on the moon is g = 1.62 m/s^2

We have to find the time.

The formula to calculate time is

`t=(2v\sin \theta)/(g)`

Substituting the values, the time will be

`\begin{gathered} t=(2*15.6*\sin 60^(\circ))/(1.62) \\ =16.68\text{ seconds} \end{gathered}`

Thus, the time taken is 16.68 seconds.