Given that we have a total population of 102, 4 out of every 12 are blue
This implies that the fraction of blue parakeets from 4 out of 12 is
![N_(blue)=(4)/(12)=(1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/ycjcpnkrbufe9h32fgalwubqvwgnlgeoil.png)
Therefore, the number of blue parakeets from the population will be
![(1)/(3)*102=\text{ 34}](https://img.qammunity.org/2023/formulas/mathematics/college/lyqz3ht0fg2c0fdyr342b40g435wmxlv1c.png)
We have 34 blue parakeets are blue
Therefore the number of parakeets that are not blue would be
![\begin{gathered} \text{Total parak}eets-Number\text{ of Blue parak}eets \\ =102-34=68 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/u8vl7lu9cyvy5l3cxn28h197759g8yfm34.png)
Hence, the number of parakeets in the population that are not blue is 68