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For the standard normal distribution shown on the right, find the probability of z occurring in the indicated region.

For the standard normal distribution shown on the right, find the probability of z-example-1

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From the graph, the z-score is -1.91, and the probability we are looking for is:


P(z>-1.91)=1-P(z\le-1.91)

From tables, we know that:


P(z\le-1.91)=0.028067

Then:


\begin{gathered} P(z>-1.91)=1-0.028067 \\ \therefore P(z>-1.91)=0.971933 \end{gathered}

The probability is 0.971933

User Needhi Agrawal
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