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triangle PQR with vertices p(6,-6) and R(9,-7) and R(7,-4) is drawn inside a rectangle as as shown below what's is the area in square units of triangle PQR

triangle PQR with vertices p(6,-6) and R(9,-7) and R(7,-4) is drawn inside a rectangle-example-1
User Raw Hasan
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1 Answer

3 votes

Answer:

3.5 square units

Step-by-step explanation:

We can model the situation as:

Now, the area of the triangle is equal to the area of the square less the areas A, B, and C.

So, the area of the square is equal to:

Area Square = Side x Side = 3 x 3 = 9

On the other hand, the area of the triangles A, B, and C are:


\begin{gathered} \text{Area A = }(Base* Height)/(2)=(2*3)/(2)=3 \\ \text{Area B=}(Base* Height)/(2)=(1*2)/(2)=1 \\ \text{Area C = }(Base* Height)/(2)=(3*1)/(2)=1.5 \end{gathered}

Therefore, the area of the triangle with vertices P, Q, and R is:

Area = Area Square - ( Area A + Area B + Area C)

Area = 9 - ( 3 + 1 + 1.5)

Area = 9 - 5.5

Area = 3.5

So, the answer is 3.5 square units

triangle PQR with vertices p(6,-6) and R(9,-7) and R(7,-4) is drawn inside a rectangle-example-1
User Hubert Perron
by
8.7k points

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