Question

What are the factors to the equation 4x2-52x + 169 121? A 4(x-1)(x+12) B 4(x + 1)(x - 12) C. 4(x + 1)(x+12) D. 4(x-1)(x - 12)

Answer 1

The given equation is,

`4x^2-52x+169=121`

Simplifying the above equation,

`\begin{gathered} 4x^2-52x+169-121=0 \\ 4x^2-52x+48=0 \end{gathered}`
`\begin{gathered} 4x^2-13*4x+4*12=0 \\ 4(x^2-13x+12)=0 \\ 4(x^2-12x-1x+12*1)=0 \\ 4(x(x-12)-1(x-12))=0 \\ 4(x-12)(x-1)=0 \end{gathered}`

Therefore, the factors of the given expression is 4(x-1)(x-12).