Question

Algebra 2. How to solve problem 4. Picture included.Please do not make this too advanced, because this isn't the sixteenth chapter but the second in my Algebra 2 textbook.

Answer 1

`\begin{gathered} 10^x=c \\ a. \\ (10^x)\cdot((1)/(10))=(c)\cdot((1)/(10)) \\ (10^x)/(10)=(c)/(10) \\ Other\text{ way} \\ (1)/(10)=10^(-1) \\ 10^x\cdot10^(-1)=10^(x-1) \\ 10^(x-1)=(c)/(10) \\ \\ b\text{.} \\ c^4 \\ \mleft(10^x\mright)^4=\mleft(c\mright)^4 \\ 10^((4x))=c^4 \\ c\text{.} \\ 10^(6x) \\ (10^x)^6=c^6 \\ 10^(6x)=c^6 \end{gathered}`